Dodgers: 3 reasons Mookie Betts will outperform Mike Trout this season

Mookie Betts and Mike Trout standing together (Photo by Adam Glanzman/Getty Images)
Mookie Betts and Mike Trout standing together (Photo by Adam Glanzman/Getty Images) /
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Mookie Betts
Mookie Betts and Mike Trout standing together (Photo by Adam Glanzman/Getty Images) /

Mookie Betts and Mike Trout are both very good, but the Los Angeles Dodger might be better this season.


For everything lost from the 2020 MLB season, fans will gain something special, as the Los Angeles Dodgers and Mookie Betts are set to face-off against the Los Angeles Angels and Mike Trout six times this year.

That means 1/10th of the Dodgers’ schedule will come against their freeway counterparts. A natural rivalry that became a lot more interesting this offseason as perhaps the only player who has come close to matching Mike Trout’s greatness arrived in Chavez Ravine.

While there is no debate that Trout remains the best player in all of baseball—he has proven himself year, after year, after year. For individual seasons, Mookie Betts has already made the argument for being considered the game’s top player.

Betts’ 2018 campaign for the Red Sox won him the American League MVP after he batted .346/.438/.640 with 32 home runs and Gold Glove Award winning defense in the outfield. He received 28 first place votes for the MVP Award that season, while Trout, who also had a spectacular year, only received one.

So as we look ahead at the 2020 season that we hope can be safely played amid the coronavirus pandemic, could Betts do it again? Could he outperform Trout this season?

Over a 60-game schedule, anything can happen. Here are three reasons why the former AL MVP could prove he’s the best player in baseball once again.

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