Dodgers fans aren’t going to like the latest Joc Pederson free agency update
Once the 2020 season concluded, it was a foregone conclusion the Los Angeles Dodgers and Joc Pederson would be parting ways. Just months prior, the team tried to trade him to the Los Angeles Angels before the deal fell through and he was … back with the Dodgers in a seemingly awkward situation.
But Joc was likely surely OK with that because it ended up resulting in a World Series title. Nonetheless, once the offseason hit, the front office made it clear to their impending free agents that they should explore opportunities elsewhere since it didn’t appear as if the Dodgers would be keen on spending due to lost profits and lingering effects from the global pandemic.
Couple those two factors, and Pederson was always as good as gone, especially since the Dodgers traded for Mookie Betts last offseason, moved Cody Bellinger to center field full time, and now have a healthy AJ Pollock ready to go (hopefully). A natural separation, one could say.
But this aspect of the potential Joc departure won’t sit well with LA fans.
Former Dodgers OF Joc Pederson is reportedly speaking with the Giants in free agency
Pederson is talking with the San Francisco Giants?! Come on, man. Anybody but them! Alex Wood already went there. We don’t need to be facing two former Dodgers upwards of 19 times per season.
Even though the Giants are going nowhere fast and Pederson really only performs at his best in the postseason, the rivalry is the rivalry, and adding the lefty slugger’s bat to a lineup that badly needs offense will only help them get better. Pederson was largely a platoon option for the Dodgers since 2014 but is hoping to get himself a starting role in free agency, which he’ll almost definitely find in San Francisco.
Some might say Pederson was under-appreciated during his time with the Dodgers. If that’s the case, those who felt that way better hope he doesn’t make them pay if he ends up signing with the Giants and belting homers against LA in 2021 and beyond.